A He ion ( ) has one electron in a state with

PHYSICS · Multi-part · Fermi University Physics · Quantum Mechanics · Symmetry, angular momentum and spin · Central potentials and canonical three-dimensional systems

Reading the Spectrum, Ch The Coulomb spectrum from wave mechanics: quantum numbers and degeneracy

Problem

A He+^+ ion (Z=2Z=2) has one electron in a state with l=1l=1. Use the effective potential Veff(r)=−Ze24πϵ0r+l(l+1)ℏ22μr2V_{\rm eff}(r) = -\dfrac{Ze^2}{4\pi\epsilon_0 r} + \dfrac{l(l+1)\hbar^2}{2\mu r^2}, with e2/4πϵ0a0=27.2 eVe^2/4\pi\epsilon_0a_0 = 27.2\,\mathrm{eV} and ℏ2/2μa02=13.6 eV\hbar^2/2\mu a_0^2 = 13.6\,\mathrm{eV}, and the levels En=−13.6 eV×Z2/n2E_n = -13.6\,\mathrm{eV}\times Z^2/n^2 with n>ln \gt l. ((a)) Find the radius, in units of a0a_0, at which VeffV_{\rm eff} has its minimum for this ion and this ll, and the value of VeffV_{\rm eff} at that minimum, in eV (report it as it comes out of the formula, negative). ((b)) Find the lowest level EnE_n of He+^+ that has an l=1l=1 state, and how far above the floor of the well it lies. ((c)) Show that for any ZZ and any allowed pair nn, ll with l≥1l \ge 1, the level EnE_n lies above the minimum of its own VeffV_{\rm eff}, and say why a bound level could not sit exactly at that minimum.

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