Hydrogen's Balmer line

PHYSICS · Multi-part · Fermi University Physics · Atomic, Molecular & Optical Physics · One-electron atoms and the origins of atomic structure · Radiative transitions, external fields and collisions

Reading the Spectrum, Ch Radial functions, orbital size and Rydberg states

Problem

Hydrogen's Balmer α\alpha line, at 656.3 nm656.3\,\mathrm{nm}, is emitted by atoms making the transitions 3s→2p3s\to2p, 3p→2s3p\to2s and 3d→2p3d\to2p. Because hydrogen's energy depends on nn alone, the 3s3s and 2s2s levels are separated by exactly the same energy as 3p3p and 2p2p. Someone argues: "since the 3s→2s3s\to2s energy gap gives the same real, observed wavelength, the 3s→2s3s\to2s transition must also be occurring and contributing to the Balmer α\alpha line." Take the hydrogen energies as En=−13.606 eV/n2E_n = -13.606\,\mathrm{eV}/n^2 and hc=1239.84 eV nmhc = 1239.84\,\mathrm{eV\,nm}. ((a)) Compute the photon energy and wavelength corresponding to the 3s→2s3s\to2s energy gap. ((b)) Apply the dipole selection rule to decide whether 3s→2s3s\to2s is allowed. ((c)) Explain the error in this reasoning.

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