Overtone absorption bands of carbon monoxide (CO) give the following vibrational…

PHYSICS · Multi-part · Fermi University Physics · Atomic, Molecular & Optical Physics · Molecular structure and spectra · Molecular structure and spectra

Reading the Spectrum, Ch Two nuclei on one curve: rotation, vibration and the spectrum of a diatomic molecule

Problem

Overtone absorption bands of carbon monoxide (CO) give the following vibrational level spacings ΔG(v)=G(v+1)−G(v)\Delta G(v) = G(v+1)-G(v): ΔG(0)=2143.3 cm−1\Delta G(0) = 2143.3\,\mathrm{cm^{-1}}, ΔG(1)=2116.7 cm−1\Delta G(1) = 2116.7\,\mathrm{cm^{-1}}, ΔG(2)=2090.1 cm−1\Delta G(2) = 2090.1\,\mathrm{cm^{-1}}, ΔG(3)=2063.5 cm−1\Delta G(3) = 2063.5\,\mathrm{cm^{-1}}. ((a)) Show that the spacings fall by a constant amount from one to the next, and use this to find ωe\omega_e and ωexe\omega_ex_e. ((b)) Extrapolate the spacings to zero (a Birge-Sponer estimate) using De≈ωe2/4ωexeD_e \approx \omega_e^2/4\omega_ex_e, and give the result in eV. ((c)) The tabulated dissociation energy of CO is De=11.16 eVD_e = 11.16\,\mathrm{eV}. Compare your estimate with this value, and say in one sentence why a two-constant fit taken from the lowest levels need not give the true well depth exactly.

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