Hydrogen bromide, HBr

PHYSICS · Multi-part · Fermi University Physics · Atomic, Molecular & Optical Physics · Molecular structure and spectra · Molecular structure and spectra

Reading the Spectrum, Ch Two nuclei on one curve: rotation, vibration and the spectrum of a diatomic molecule

Problem

Hydrogen bromide, HBr, has vibrational constants

\omega_e = 2649.67\,\mathrm{cm^{-1}}

and

\omega_ex_e = 45.21\,\mathrm{cm^{-1}}

, and a rotational constant

B_0 = 8.465\,\mathrm{cm^{-1}}

in its lowest vibrational level. ((a)) Find the band origin

\tilde\nu_0 = \omega_e - 2\omega_ex_e

of the fundamental (

v=0\to1

) absorption band. ((b)) Using

B_0

, calculate the wavenumbers of

R(0)

R(1)

R(2)

and

P(1)

P(2)

P(3)

. ((c)) State the width of the empty gap at the centre of the band and confirm that no line falls exactly at

\tilde\nu_0

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