A rocket frame moves at along the common axis of the ground frame

PHYSICS · Multi-part · Fermi University Physics · Relativity & Gravitation · Special relativity: spacetime and kinematics · Special relativity: spacetime and kinematics

Relativity and Gravitation, Ch Time dilation, length contraction and simultaneity

Problem

A rocket frame S′S' moves at v=0.500cv = 0.500c along the common +x+x axis of the ground frame SS, the axes are parallel and the origins coincide at t=t′=0t = t' = 0 (c=2.998×108 m s−1c = 2.998 \times 10^{8}\ \mathrm{m\,s^{-1}}). Two service lamps are fixed to the rocket at x′=0x' = 0 (lamp AA) and x′=480 mx' = 480\ \mathrm{m} (lamp BB), with BB ahead in the direction of motion. In the rocket frame both lamps flash at t′=0t' = 0, so the flash events in S′S' are A:(t′=0, x′=0)A: (t' = 0,\ x' = 0) and B:(t′=0, x′=480 m)B: (t' = 0,\ x' = 480\ \mathrm{m}). ((a)) Give the ground-frame coordinates (t,x)(t, x) of the flash at lamp BB. (The flash at AA is at (0,0)(0, 0) by the choice of origins.) ((b)) Give the distance between the two lamps as measured in the ground frame. ((c)) A student reads off your answer to (a) and says "the lamps are xB−xAx_B - x_A apart in the ground frame". Using your two answers, say in one or two sentences why that figure is not the ground-frame length.

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