A traveller leaves Earth at and flies at a steady to a station at rest relative to Earth

PHYSICS · Multi-part · Fermi University Physics · Relativity & Gravitation · Special relativity: spacetime and kinematics · Special relativity: spacetime and kinematics

Relativity and Gravitation, Ch Time dilation, length contraction and simultaneity

Problem

A traveller leaves Earth at t=0t = 0 and flies at a steady v=0.600cv = 0.600c to a station at rest relative to Earth, a distance D=6.00D = 6.00 light-years away as measured in the Earth frame SS. On reaching the station she turns round in a negligible time and returns at the same speed. Treat the Earth frame SS, the outbound frame SoutS_{\rm out} (moving at +v+v along the xx axis from Earth to the station) and the inbound frame SinS_{\rm in} (moving at −v-v) as inertial, each in standard configuration with SS and each with clocks synchronised in its own frame. Ignore gravitation. ((a)) Find the elapsed time of the round trip on Earth clocks, and the elapsed time on the traveller's own clock. ((b)) Name the event "the traveller reaches the station" by its coordinates (t,x)(t, x) in SS. Find the reading of the Earth clock at the Earth event that SoutS_{\rm out} judges simultaneous with it, and the reading at the Earth event that SinS_{\rm in} judges simultaneous with it. ((c)) Using your two readings from (b) and the time dilation of the Earth clock on each leg as judged by the traveller, account for the whole of the Earth elapsed time found in (a), and say in one sentence what breaks the symmetry between the two twins.

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