A free-falling capsule is at a distance from the centre of a brown dwarf of mass

PHYSICS · Multi-part · Fermi University Physics · Relativity & Gravitation · Newtonian gravitation as a field theory · Newtonian gravitation as a field theory

Relativity and Gravitation, Ch Tidal forces and the Newtonian tidal field

Problem

A free-falling capsule is at a distance r=6.00×107 mr = 6.00\times10^{7}\ \mathrm{m} from the centre of a brown dwarf of mass M=5.00×1028 kgM = 5.00\times10^{28}\ \mathrm{kg}, treated as a point mass; no forces other than gravity act. Inside the capsule the xx axis points along the outward radius and the yy axis is transverse. A free test particle of negligible mass sits at separation ξ⃗\vec\xi from the capsule's centre, of magnitude ξ\xi, in the xx–yy plane and making an angle θ\theta with the +x+x axis (so ξx=ξcos⁡θ\xi_x = \xi\cos\theta, ξy=ξsin⁡θ\xi_y = \xi\sin\theta). Work to first order in ξ/r\xi/r. ((a)) From the point-mass tidal field in these axes, derive the two components of the relative acceleration Δa⃗\Delta\vec a and show that its magnitude is GMξr31+3cos⁡2θ\dfrac{GM\xi}{r^{3}}\sqrt{1+3\cos^{2}\theta}. ((b)) Show that the sum of the three diagonal entries of the tidal field vanishes here, and state in one sentence what that means for a small ball of dust released in the capsule. ((c)) For ξ=3.00 m\xi = 3.00\ \mathrm{m} and θ=30.0∘\theta = 30.0^{\circ}, evaluate Δax\Delta a_x, Δay\Delta a_y, the magnitude of Δa⃗\Delta\vec a, and the angle between Δa⃗\Delta\vec a and the outward radius.

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