A liner of proper length leaves rest at the origin of an inertial frame at and burns…

PHYSICS · Multi-part · Fermi University Physics · Relativity & Gravitation · The equivalence principle and gravity as geometry · The equivalence principle and gravity as geometry

Relativity and Gravitation, Ch Accelerated observers, hyperbolic motion and the equivalence principle

Problem

A liner of proper length 60 m60\ \mathrm{m} leaves rest at the origin of an inertial frame SS at t=τ=0t = \tau = 0 and burns along the common +x+x axis in two stages, always in the same direction. In the first stage its accelerometer reads a1=9.8 m s−2a_1 = 9.8\ \mathrm{m\,s^{-2}} for a proper time τ1=1.5×107 s\tau_1 = 1.5\times 10^{7}\ \mathrm{s}; in the second it reads a2=4.9 m s−2a_2 = 4.9\ \mathrm{m\,s^{-2}} for a further proper time τ2=2.0×107 s\tau_2 = 2.0\times 10^{7}\ \mathrm{s}. Nose and tail may be given the same proper acceleration to the accuracy wanted here. ((a)) Find the liner's speed measured in SS at the end of the second stage, and the Lorentz factor γ\gamma of the liner in SS there. ((b)) Clocks sit at the nose and at the tail. Working to first order in ah/c2a h/c^{2}, find how much time the nose clock gains on the tail clock during the second stage alone. ((c)) During the second stage the crew feel a steady 4.9 m s−24.9\ \mathrm{m\,s^{-2}} and say they might as well be resting on the surface of a spherical planet of radius 4.0×106 m4.0\times 10^{6}\ \mathrm{m} whose surface field strength is 4.9 m s−24.9\ \mathrm{m\,s^{-2}}. In a sealed capsule falling freely just above that planet's surface, two marbles are released from rest one directly above the other, 2.0 m2.0\ \mathrm{m} apart. Find their relative acceleration just after release, and the time for the gap to grow by 10 μm10\ \mu\mathrm{m}.

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