In 1783 Michell set the Newtonian escape speed of a body equal to ,

PHYSICS · Multi-part · Fermi University Physics · Relativity & Gravitation · Relativistic stars and compact objects · Relativistic stars and compact objects

Relativity and Gravitation, Ch Escape velocity, the Schwarzschild radius and the idea of a black hole

Problem

In 1783 Michell set the Newtonian escape speed of a body equal to cc, 12c2=GM/R\tfrac12 c^2 = GM/R, and so found a radius from which "light could not escape". A student prefers a different Newtonian argument: since light of energy EE carries E/c2E/c^2 where a mass would sit, the student writes the condition for light to be bound as mc2=GMm/Rmc^2 = GMm/R and obtains a radius smaller than Michell's. Consider a black hole of mass M=12 M⊙M = 12\,M_\odot, with M⊙=1.989×1030 kgM_\odot = 1.989\times10^{30}\ \mathrm{kg}, G=6.674×10−11 N m2 kg−2G = 6.674\times10^{-11}\ \mathrm{N\,m^2\,kg^{-2}}, c=2.998×108 m s−1c = 2.998\times10^{8}\ \mathrm{m\,s^{-1}}. ((a)) Compute the radius the student's condition gives. ((b)) Compute the Schwarzschild radius rs=2GM/c2r_s = 2GM/c^2, the radius that the full theory of gravity also gives for the horizon. ((c)) An astronaut of radial extent ξ=1.7 m\xi = 1.7\ \mathrm{m} falls freely through the horizon. Using the Newtonian tidal field of Chapter 7, Δa=2GMξ/r3\Delta a = 2GM\xi/r^3, compute the tidal stretch along the astronaut's body at r=rsr = r_s. In your solution, state in one or two sentences what is wrong with both Newtonian arguments, even though one of them delivers the accepted radius.

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