A point monopole source in air has velocity potential

PHYSICS · Subjective · Fermi University Physics · Oscillations, Waves & Acoustics · Acoustics of fluids: generation, propagation and attenuation · Acoustics of fluids: generation, propagation and attenuation

Signal Speeds in Fluids, Ch Sound in a moving, absorbing fluid: sources, refraction and loss

Problem

A point monopole source in air has velocity potential ϕ(r,t)=−Q04πrcos⁡(kr−ωt)\phi(r,t) = -\dfrac{Q_0}{4\pi r}\cos(kr-\omega t), where Q0Q_0 is the amplitude of the volume flow it injects, k=ω/c0k=\omega/c_0, and rr is distance from the source. The chapter's power formula used only the far field; here we keep every term. (a) Find the pressure perturbation p′=−ρ0 ∂ϕ/∂tp'=-\rho_0\,\partial\phi/\partial t and the radial velocity ur′=∂ϕ/∂ru_r'=\partial\phi/\partial r exactly, at any rr, with no far-field approximation. (b) Split ur′u_r' into a part in phase with p′p' and a part a quarter-cycle out of phase with it. Show that only the in-phase part contributes to ⟨p′ur′⟩\langle p'u_r'\rangle, and hence that 4πr2⟨p′ur′⟩=ρ0ω2Q02/8πc04\pi r^2\langle p'u_r'\rangle=\rho_0\omega^2Q_0^2/8\pi c_0 at every radius, close to the source as well as far away. (c) For Q0=1.3×10−3 m3 s−1Q_0=1.3\times10^{-3}\,\mathrm{m^3\,s^{-1}} and f=100 Hzf=100\,\mathrm{Hz} in air (ρ0=1.204 kg m−3\rho_0=1.204\,\mathrm{kg\,m^{-3}}, c0=343.2 m s−1c_0=343.2\,\mathrm{m\,s^{-1}}), evaluate the radiated power, and find the ratio of the amplitude of the out-of-phase velocity to that of the in-phase velocity at r=0.10 mr=0.10\,\mathrm{m}.

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