Chapter 5 gives the convected wave equation for a small velocity-potential…

PHYSICS · Multi-part · Fermi University Physics · Mathematical Methods for Physics · Fluids & Continuum Physics · Waves, acoustics and compressible flow

Signal Speeds in Fluids, Ch Steady compressible flow: energy, stagnation and the Mach number

Problem

Chapter 5 gives the convected wave equation for a small velocity-potential perturbation ϕ′\phi' in a uniform stream UU along xx, with free-stream sound speed c∞c_\infty: (∂∂t+U∂∂x)2ϕ′=c∞2(∂2ϕ′∂x2+∂2ϕ′∂y2).\left(\frac{\partial}{\partial t}+U\frac{\partial}{\partial x}\right)^2\phi' = c_\infty^2\left(\frac{\partial^2\phi'}{\partial x^2}+\frac{\partial^2\phi'}{\partial y^2}\right). For steady flow past a thin body ϕ′\phi' does not depend on tt. ((a)) Show that the steady form of this equation is (1−M∞2)ϕxx+ϕyy=0,M∞=U/c∞.(1-M_\infty^2)\phi_{xx}+\phi_{yy}=0,\qquad M_\infty = U/c_\infty. ((b)) For M∞>1M_\infty > 1 this is a wave equation in which xx plays the part that time plays in Chapter 2's shallow-water characteristics, where a disturbance travels along dx/dt=u±cdx/dt = u\pm c. Write the equation in the form ϕxx=β−2ϕyy\phi_{xx} = \beta^{-2}\phi_{yy} with β=M∞2−1\beta=\sqrt{M_\infty^2-1}, find its two families of characteristic lines in the (x,y)(x,y) plane, and identify them with the Mach lines, giving the Mach angle μ\mu in terms of M∞M_\infty. ((c)) Explain, from the sign of 1−M∞21-M_\infty^2, why running the same construction at M∞<1M_\infty < 1 gives no real characteristic directions, and relate this to the absence of any confined zone of silence in the subsonic flow that instead obeys the Prandtl-Glauert rule. ((d)) A thin wedge in a stream at M∞=1.8M_\infty = 1.8 turns the flow through θ=3.0∘\theta = 3.0^\circ at a sharp corner, taken as the origin, with the flow along +x+x and yy measured away from the wall. Upstream of the corner the static pressure is p∞=80.0 kPap_\infty = 80.0\,\mathrm{kPa} and γ=1.4\gamma = 1.4. State whether the point (x,y)=(10.0 m,4.0 m)(x,y) = (10.0\,\mathrm{m}, 4.0\,\mathrm{m}) lies inside the region reached by the corner's disturbance, and, if it does, use Ackeret's formula Cp=2θ/βC_p = 2\theta/\beta together with the ideal-gas relation ρU2=γpM2\rho U^2 = \gamma p M^2 to find the static pressure there.

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