A metal conducts through one electron band and one hole band

PHYSICS · Subjective · Fermi University Physics · Condensed Matter, Materials & Soft Matter · Electronic transport in solids · Electronic transport in solids

Solid State Physics, Ch The Boltzmann equation and electrical transport

Problem

A metal conducts through one electron band and one hole band, each carrier scattering with its own relaxation time so that each has a well-defined mobility. The carrier densities and mobilities are ne=2.0×1028 m−3n_e = 2.0\times10^{28}\,\mathrm{m^{-3}}, μn=55 cm2 V−1s−1\mu_n = 55\,\mathrm{cm^2\,V^{-1}s^{-1}} (5.5×10−3 m2 V−1s−15.5\times10^{-3}\,\mathrm{m^2\,V^{-1}s^{-1}}) and nh=1.0×1028 m−3n_h = 1.0\times10^{28}\,\mathrm{m^{-3}}, μp=20 cm2 V−1s−1\mu_p = 20\,\mathrm{cm^2\,V^{-1}s^{-1}} (2.0×10−3 m2 V−1s−12.0\times10^{-3}\,\mathrm{m^2\,V^{-1}s^{-1}}). Calculate the low-field Hall coefficient RHR_H of this metal, taking the elementary charge as e=1.602×10−19 Ce=1.602\times10^{-19}\,\mathrm{C}.

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