A metal conducts through one electron band and one hole band

PHYSICS · Multi-part · Fermi University Physics · Condensed Matter, Materials & Soft Matter · Electronic transport in solids · Electronic transport in solids

Solid State Physics, Ch The Boltzmann equation and electrical transport

Problem

A metal conducts through one electron band and one hole band, each an isotropic Boltzmann band with its own density and mobility, ne,μen_e,\mu_e and nh,μhn_h,\mu_h. With B\mathbf{B} along zz, each band on its own has the conductivity tensor of a single band, σ(i)=σi1+βi2(1∓βi±βi1),σi=nieμi,βi=μiB,\sigma^{(i)}=\frac{\sigma_i}{1+\beta_i^2}\begin{pmatrix}1&\mp\beta_i\\ \pm\beta_i&1\end{pmatrix},\qquad\sigma_i=n_ie\mu_i,\quad\beta_i=\mu_iB, with the upper signs for the electron band and the lower signs for the hole band. ((a)) Add the two tensors, invert the sum, and show that the transverse magnetoresistance is Δρρ≡ρxx(B)−ρxx(0)ρxx(0)=nenhμeμh(μe+μh)2B2(neμe+nhμh)2+(nh−ne)2μe2μh2B2.\frac{\Delta\rho}{\rho}\equiv\frac{\rho_{xx}(B)-\rho_{xx}(0)}{\rho_{xx}(0)}=\frac{n_en_h\mu_e\mu_h(\mu_e+\mu_h)^2B^2}{(n_e\mu_e+n_h\mu_h)^2+(n_h-n_e)^2\mu_e^2\mu_h^2B^2}. ((b)) Find the high-field limit of Δρ/ρ\Delta\rho/\rho when nh≠nen_h\neq n_e, and show that it grows as B2B^2 without limit when nh=nen_h=n_e. ((c)) Aluminium, treated as in the worked example on its Hall coefficient, has 1.061.06 holes and 0.060.06 electrons per atom, with μe=5μh\mu_e=5\mu_h. Evaluate its saturated Δρ/ρ\Delta\rho/\rho at high field.

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