The derivation of the Leavitt law treated the instability strip as vertical

PHYSICS · Multi-part · Fermi University Physics · Astrophysics & Cosmology · Observational foundations and instrumentation · Stellar structure, energy generation and evolution

Stars from the Inside, Ch Pulsating stars: the kappa mechanism, the Leavitt law and asteroseismology

Problem

The derivation of the Leavitt law treated the instability strip as vertical, every Cepheid at the same TeffT_{\rm eff}. Suppose instead that the strip's centre line tilts towards cooler temperatures at higher luminosity, Teff∝L−bT_{\rm eff} \propto L^{-b} with bb a small positive constant. Keep Π∝R3/2M−1/2\Pi \propto R^{3/2}M^{-1/2}, L∝R2Teff4L \propto R^2T_{\rm eff}^4 and L∝MaL \propto M^a. ((a)) Show that Π∝L3/4+3b−1/2a\Pi \propto L^{3/4 + 3b - 1/2a}. ((b)) For a=3.5a = 3.5 and b=0.05b = 0.05, find the exponent and the slope dlog⁡L/dlog⁡Π\mathrm{d}\log L/\mathrm{d}\log\Pi, and compare the slope with the vertical strip's 1.61.6 and with the calibrated 0.970.97. ((c)) With a=3.5a = 3.5, what value of bb would the tilt alone need to bring the slope down to 0.970.97? By what factor would TeffT_{\rm eff} then fall across the two decades of luminosity that Cepheids span, and is that compatible with a strip that runs from about 60006000 to 7500 K7500\,\mathrm{K}?

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