In muon decay

PHYSICS · Multi-part · Fermi University Physics · Particle Physics & Quantum Fields · Particles, interactions and experiment · Particles, interactions and experiment

Symmetry and Flavour, Ch From amplitude to rate: Lorentz-invariant phase space, widths and cross sections

Problem

In muon decay μ−→e−νˉeνμ\mu^-\to e^-\bar\nu_e\nu_\mu, mediated by a point-like weak interaction, the electron energy spectrum in the muon rest frame (electron mass neglected in the dynamics) is dΓdEe=GF2mμ212π3Ee2(3−4Eemμ).\frac{\mathrm{d}\Gamma}{\mathrm{d}E_e}=\frac{G_F^2m_\mu^2}{12\pi^3}E_e^2\left(3-\frac{4E_e}{m_\mu}\right). ((a)) Treat the two neutrinos together as a single recoiling system XX of invariant mass mXm_X, so that the decay is kinematically a two-body decay μ→e+X\mu\to e+X. Using the two-body decay kinematics (the energy formula that accompanies the Kallen-function momentum p∗p^*), write the electron's rest-frame energy Ee∗E_e^* as a function of mμm_\mu, mem_e and mXm_X. ((b)) The two neutrinos are massless, so mXm_X can range down to zero (when they move collinearly). Use this to derive the maximum electron energy Eemax⁡E_e^{\max} allowed by kinematics, in terms of mμm_\mu and mem_e alone. ((c)) Evaluate Eemax⁡E_e^{\max} numerically for mμ=105.658 MeVm_\mu=105.658\,\mathrm{MeV} and me=0.511 MeVm_e=0.511\,\mathrm{MeV}, and compare it with the massless-electron approximation mμ/2m_\mu/2 used implicitly in the spectrum formula above, quoting the difference in keV\mathrm{keV}.

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