Starting from | 32, 12 = 23 ,|1,0 | 12, 12 + 13 ,|1,1 | 12,- 12

PHYSICS · Subjective · Fermi University Physics · Quantum Mechanics · Symmetry, angular momentum and spin · Symmetry, angular momentum and spin

Symmetry and Flavour, Ch Isospin as a group: SU(2), Clebsch-Gordan ratios and G-parity

Problem

Starting from ∣32,12⟩=23 ∣1,0⟩∣12,12⟩+13 ∣1,1⟩∣12,−12⟩,|\tfrac32,\tfrac12\rangle=\sqrt{\tfrac23}\,|1,0\rangle|\tfrac12,\tfrac12\rangle+\sqrt{\tfrac13}\,|1,1\rangle|\tfrac12,-\tfrac12\rangle, apply the lowering operator T−=T−(1)+T−(2)T_-=T_-^{(1)}+T_-^{(2)} once more, using T−∣I,M⟩=I(I+1)−M(M−1) ∣I,M−1⟩T_-|I,M\rangle=\sqrt{I(I+1)-M(M-1)}\,|I,M-1\rangle on each factor, to obtain ∣32,−12⟩|\tfrac32,-\tfrac12\rangle as a combination of ∣1,−1⟩∣12,12⟩|1,-1\rangle|\tfrac12,\tfrac12\rangle and ∣1,0⟩∣12,−12⟩|1,0\rangle|\tfrac12,-\tfrac12\rangle. Then write down the orthogonal, normalised combination ∣12,−12⟩|\tfrac12,-\tfrac12\rangle of the same two basis states, fixing its overall sign by the Condon-Shortley convention, which takes the coefficient of the term with the larger first-factor I3I_3 to be positive.

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