A is captured at rest by a deuteron from the atomic orbital ( ) of the atom

PHYSICS · Multi-part · Fermi University Physics · Quantum Mechanics · Particle Physics & Quantum Fields · Symmetry, groups and the quark model

Symmetry and Flavour, Ch Parity, charge conjugation and time reversal as operators, and the CPT theorem

Problem

A π−\pi^- is captured at rest by a deuteron from the 1s1s atomic orbital (L=0L=0) of the π−d\pi^-d atom, giving π−d→nn\pi^-d\to nn about three quarters of the time. The deuteron has JP=1+J^P=1^+, the pion has spin 00, and each neutron has intrinsic parity P(n)=+1P(n)=+1. ((a)) Give the total angular momentum JJ of the atomic state just before capture. ((b)) List the two-neutron spectroscopic states 2S+1LJ^{2S+1}L_J with this value of JJ, for S=0S=0 and S=1S=1 and L=0,1,2L=0,1,2. ((c)) Eliminate the states forbidden by the Pauli principle for two identical neutrons (which requires L+SL+S even), and identify the single surviving state. ((d)) Use that surviving state to determine P(π−)P(\pi^-).

Related theory

Browse the problem library