A duct's cross-section occupies the strip with earthed walls at and
PHYSICS · Multi-part · Fermi University Physics · Electricity, Magnetism & Electromagnetism · Conductors, capacitance and boundary-value electrostatics · Conductors, capacitance and boundary-value electrostatics
The Boundary-Value Problem, Ch Separation of variables in Cartesian geometry
Problem
A duct's cross-section occupies the strip 0≤x≤a with earthed walls at x=0 and x=a, and extends upward without limit in y: there is no wall at any finite y. The wall at y=0 is held at some potential V(x,0)=f(x) whose detailed shape does not matter here. Because the duct is open at large y, the physical requirement replacing a fourth wall is that V(x,y)→0 as y→∞ for every x in (0,a), with V bounded throughout.
((a)) Substitute V(x,y)=X(x)Y(y) and separate Laplace's equation, writing the two ordinary equations in terms of one constant μ.
((b)) Using only the conditions X(0)=X(a)=0 on the earthed side walls, show by testing both signs of μ that μ must be negative, and find the allowed values of k where μ=−k2.
((c)) With μ=−k2, the equation for Y is Y′′=k2Y, whose general solution is a sum of two exponentials. Show that only one combination is consistent with V→0 as y→∞, and write it down.