A long conducting duct has square cross-section of side

PHYSICS · Multi-part · Fermi University Physics · Mathematical Methods for Physics · Electricity, Magnetism & Electromagnetism · Conductors, capacitance and boundary-value electrostatics

The Boundary-Value Problem, Ch Separation of variables in Cartesian geometry

Problem

A long conducting duct has square cross-section of side a=12 cma=12\,\mathrm{cm}. Two adjacent walls, x=0x=0 and y=0y=0, are earthed. The other two, x=ax=a and y=ay=a, which meet at the corner (a,a)(a,a), are both held at the same potential V0=90 VV_0=90\,\mathrm{V}; thin insulating strips separate each live wall from the earthed wall it touches (there is no potential jump at the shared corner (a,a)(a,a), since both walls there are at V0V_0). ((a)) Decompose the problem into two one-live-wall duct problems, each of the type already solved: problem A has x=ax=a at V0V_0 with x=0x=0, y=0y=0 and y=ay=a earthed; problem B has y=ay=a at V0V_0 with x=0x=0, x=ax=a and y=0y=0 earthed. Write down the series solution for each. ((b)) Without summing any series, use the four-fold superposition of the single-live-wall problem (four rotated copies of one live wall adding to V0V_0 everywhere, each contributing exactly V0/4V_0/4 at the centre) to state the exact potential at the centre (a/2,a/2)(a/2,a/2) of this duct with two adjacent live walls. ((c)) Using the first two non-zero terms of each series, evaluate VV at (3a/4, a/4)(3a/4,\,a/4), one quarter of the way in from the y=0y=0 wall and three-quarters of the way across towards the x=ax=a wall.

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