This problem has two independent halves

PHYSICS · Multi-part · Fermi University Physics · Electricity, Magnetism & Electromagnetism · Conductors, capacitance and boundary-value electrostatics · Conductors, capacitance and boundary-value electrostatics

The Boundary-Value Problem, Ch Separation of variables in spherical geometry

Problem

This problem has two independent halves, each pairing a spherical-geometry result with a method met earlier. Parts ((a)) to (c) find a dipole by images; parts (d) to (f) compare expansion coefficients across two geometries. A conducting sphere of radius a=2.0 cma = 2.0\,\mathrm{cm}, centred at the origin and held at zero potential (grounded), sits between two point charges on the zz axis: q=+4.0 nCq = +4.0\,\mathrm{nC} at z=+Dz = +D and −q-q at z=−Dz = -D, with D=40 cmD = 40\,\mathrm{cm}. Because D≫aD \gg a, these two charges act on the sphere as an almost uniform applied field of strength E0=2q/(4πε0D2)E_0 = 2q/(4\pi\varepsilon_0D^2), pointing along −z^-\hat{\mathbf{z}} at the sphere. (a) Using the image charge for a grounded sphere (a charge qq at distance DD from the centre has an image −qa/D-qa/D at distance a2/Da^2/D), write down the two image charges and their positions for the two given charges. ((b)) Find the dipole moment pimp_{\rm im} formed by these two image charges. ((c)) Compare pimp_{\rm im} with the value predicted from the polarisability of a conducting sphere, p=4πε0a3E0p = 4\pi\varepsilon_0a^3E_0, and confirm the two routes agree. ((d)) An infinite duct of rectangular cross-section 0≤x≤w0 \le x \le w (with w=2.0 mw = 2.0\,\mathrm{m}) has one wall, at y=0y=0, held at V(x,0)=+V0V(x,0) = +V_0 for 0<x<1.0 m0 < x < 1.0\,\mathrm{m} and V(x,0)=−V0V(x,0) = -V_0 for 1.0 m<x<2.0 m1.0\,\mathrm{m} < x < 2.0\,\mathrm{m}, with V0=60 VV_0 = 60\,\mathrm{V}, and V=0V=0 at x=0x=0 and x=wx=w. Writing V(x,0)=∑n=1∞cnsin⁡(nπx/w)V(x,0) = \sum_{n=1}^{\infty}c_n\sin(n\pi x/w), use the orthogonality integral over xx to find the first two non-zero coefficients cnc_n. ((e)) A sphere of radius aa is held at V(θ)=+V0V(\theta) = +V_0 on the upper hemisphere (0≤θ<π/20 \le \theta < \pi/2) and −V0-V_0 on the lower hemisphere, with the same V0=60 VV_0 = 60\,\mathrm{V}. Writing the interior potential as V(r,θ)=∑ℓAℓ(r/a)ℓPℓ(cos⁡θ)V(r,\theta) = \sum_{\ell} A_\ell(r/a)^\ell P_\ell(\cos\theta), use the orthogonality integral over cos⁡θ\cos\theta to find A1A_1 and A3A_3. ((f)) Both boundary data sets have a discontinuous jump. State, from the sizes found in (d) and (e), how each coefficient sequence decays with its index, and what feature of the data this decay is tied to.

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