PHYSICS · Multi-part · Fermi University Physics · Electricity, Magnetism & Electromagnetism · Conductors, capacitance and boundary-value electrostatics · Conductors, capacitance and boundary-value electrostatics
The Boundary-Value Problem, Ch Separation of variables in spherical geometry
Problem
This problem has two independent halves, each pairing a spherical-geometry result with a method met earlier. Parts
((a)) to (c) find a dipole by images; parts (d) to (f) compare expansion coefficients across two geometries. A conducting sphere of radius a=2.0cm, centred at the origin and held at zero potential (grounded), sits between two point charges on the z axis: q=+4.0nC at z=+D and −q at z=−D, with D=40cm. Because D≫a, these two charges act on the sphere as an almost uniform applied field of strength E0=2q/(4πε0D2), pointing along −z^ at the sphere. (a) Using the image charge for a grounded sphere (a charge q at distance D from the centre has an image −qa/D at distance a2/D), write down the two image charges and their positions for the two given charges.
((b)) Find the dipole moment pim formed by these two image charges.
((c)) Compare pim with the value predicted from the polarisability of a conducting sphere, p=4πε0a3E0, and confirm the two routes agree.
((d)) An infinite duct of rectangular cross-section 0≤x≤w (with w=2.0m) has one wall, at y=0, held at V(x,0)=+V0 for 0<x<1.0m and V(x,0)=−V0 for 1.0m<x<2.0m, with V0=60V, and V=0 at x=0 and x=w. Writing V(x,0)=∑n=1∞cnsin(nπx/w), use the orthogonality integral over x to find the first two non-zero coefficients cn.
((e)) A sphere of radius a is held at V(θ)=+V0 on the upper hemisphere (0≤θ<π/2) and −V0 on the lower hemisphere, with the same V0=60V. Writing the interior potential as V(r,θ)=∑ℓAℓ(r/a)ℓPℓ(cosθ), use the orthogonality integral over cosθ to find A1 and A3.
((f)) Both boundary data sets have a discontinuous jump. State, from the sizes found in (d) and (e), how each coefficient sequence decays with its index, and what feature of the data this decay is tied to.