(a) Starting from Laplace's equation in cylindrical coordinates, ^2V = 1 s s (s V s )…

PHYSICS · Subjective · Fermi University Physics · Electricity, Magnetism & Electromagnetism · Electrostatic fields and potential · Conductors, capacitance and boundary-value electrostatics

The Boundary-Value Problem, Ch Cylindrical geometry, edges, and what a field does to a dipole

Problem

(a) Starting from Laplace's equation in cylindrical coordinates, ∇2V=1s∂∂s(s∂V∂s)+1s2∂2V∂ϕ2+∂2V∂z2=0,\nabla^2V = \frac{1}{s}\frac{\partial}{\partial s}\left(s\frac{\partial V}{\partial s}\right) + \frac{1}{s^2}\frac{\partial^2V}{\partial\phi^2} + \frac{\partial^2V}{\partial z^2} = 0, separate V(s,ϕ,z)=R(s)Φ(ϕ)Z(z)V(s,\phi,z) = R(s)\Phi(\phi)Z(z) and show that it splits into three ordinary differential equations linked by two separation constants, kk (for ZZ) and mm (for Φ\Phi), and write down the equation obeyed by R(s)R(s). (b) Two earthed conducting half-planes meet along the zz axis, with the field region between them opening through an angle β\beta. Using the k=0k=0 case of part (a), impose V=0V=0 on both faces and finiteness at the edge, and derive the leading power-law dependence E,σ∝sπ/β−1E,\sigma \propto s^{\pi/\beta - 1} of the field and surface charge density near the edge. (c) A small body of polarisability α\alpha sits in a static, non-uniform applied field E(r)\mathbf{E}(\mathbf{r}) that is curl-free, so that it acquires an induced dipole moment p=αE\mathbf{p}=\alpha\mathbf{E}. Starting from the force law for a rigid dipole, F=(p⋅∇)E\mathbf{F} = (\mathbf{p}\cdot\nabla)\mathbf{E}, derive the force on the induced dipole in terms of ∇(E2)\nabla(E^2), and hence show that its energy is −12αE2-\tfrac12\alpha E^2.

Browse the problem library