A uniform, stationary conductor of constant permeability and conductivity obeys the…

PHYSICS · Multi-part · Fermi University Physics · Mathematical Methods for Physics · Electricity, Magnetism & Electromagnetism · Partial differential equations and boundary-value problems

The Boundary-Value Problem, Ch The quasi-static approximation, eddy currents and the skin effect

Problem

A uniform, stationary conductor of constant permeability μ\mu and conductivity σ\sigma obeys the quasi-static equations ∇×E=−∂B/∂t\nabla\times\mathbf{E} = -\partial\mathbf{B}/\partial t, ∇×B=μσE\nabla\times\mathbf{B} = \mu\sigma\mathbf{E} and ∇⋅B=0\nabla\cdot\mathbf{B} = 0 (the displacement current has been dropped). ((a)) Starting from these three equations, derive the magnetic diffusion equation ∇2B=μσ ∂B/∂t\nabla^2\mathbf{B} = \mu\sigma\,\partial\mathbf{B}/\partial t. ((b)) The conductor occupies the half-space z>0z > 0 and its surface at z=0z=0 is driven so that B(0,t)=B0cos⁡(ωt)y^\mathbf{B}(0,t) = B_0\cos(\omega t)\hat{\mathbf{y}}. Writing B=y^ Re[B~(z)e−iωt]\mathbf{B} = \hat{\mathbf{y}}\,\mathrm{Re}[\tilde{B}(z)e^{-i\omega t}] and trying B~(z)=B0eiκz\tilde{B}(z) = B_0e^{i\kappa z}, find the equation obeyed by κ\kappa, solve it using i=(1+i)/2\sqrt{i} = (1+i)/\sqrt{2}, discard the root that is unphysical for z>0z>0, and show that B(z,t)=B0e−z/δcos⁡(z/δ−ωt)y^\mathbf{B}(z,t) = B_0e^{-z/\delta}\cos(z/\delta - \omega t)\hat{\mathbf{y}} with δ=2/μσω\delta = \sqrt{2/\mu\sigma\omega}. ((c)) Now consider a sheet of thickness dd with d≪δd \ll \delta, lying in the yzyz-plane, carrying the same field B0cos⁡ωt y^B_0\cos\omega t\,\hat{\mathbf{y}} but now taken as uniform across the thickness because d≪δd\ll\delta. Using Faraday's law on a rectangular loop in the xzxz-plane that reaches ±x\pm x from the mid-plane, find Ez(x)E_z(x), form the Ohmic dissipation per unit volume σEz2\sigma E_z^2, average over one cycle and over the thickness, and show that the eddy-current loss per unit volume is σω2B02d2/24\sigma\omega^2B_0^2d^2/24.

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