A collimated laser beam of intensity (power per unit area) travels along the -axis in…

PHYSICS · Multi-part · Fermi University Physics · Electricity, Magnetism & Electromagnetism · Relativity & Gravitation · Relativistic dynamics and fields in flat spacetime

The Geometry of Gravity, Ch The stress-energy tensor and relativistic continua

Problem

A collimated laser beam of intensity (power per unit area) I=3.0×108 W m−2I = 3.0\times10^{8}\ \mathrm{W\,m^{-2}} travels along the xx-axis in vacuum. Someone reasons as follows: The energy density is T00=I/c=1.0 J m−3T^{00} = I/c = 1.0\ \mathrm{J\,m^{-3}}. The energy flux through a surface of constant xx is just the intensity itself, so T0x=I=3.0×108 J m−2 s−1T^{0x} = I = 3.0\times10^{8}\ \mathrm{J\,m^{-2}\,s^{-1}}. The momentum density is Tx0=T00=1.0 J m−3T^{x0} = T^{00} = 1.0\ \mathrm{J\,m^{-3}}, since for a light beam T00=Txx=T0x=Tx0T^{00}=T^{xx}=T^{0x}=T^{x0} should all be equal. But my numbers give T0x=3.0×108T^{0x} = 3.0\times10^8 while Tx0=1.0T^{x0}=1.0, so this beam's stress-energy tensor is not symmetric. ((a)) Find the error in this reasoning. ((b)) Give the correct common value of T0x=Tx0T^{0x}=T^{x0} (and hence of T00=TxxT^{00}=T^{xx} too) for this beam.

Related theory

Browse the problem library