A steel wire lies along the axis under a tension of

PHYSICS · Multi-part · Fermi University Physics · Fluids & Continuum Physics · Relativity & Gravitation · Relativistic dynamics and fields in flat spacetime

The Geometry of Gravity, Ch The stress-energy tensor and relativistic continua

Problem

A steel wire lies along the xx axis under a tension of σ=1.0×109 Pa\sigma=1.0\times10^9\ \mathrm{Pa}, close to the breaking stress of a strong steel. In the wire's rest frame its stress-energy tensor is Tμν=diag(ρ,−σ,0,0)T^{\mu\nu}=\mathrm{diag}(\rho,-\sigma,0,0): energy density ρ=ρmc2\rho=\rho_{\rm m}c^2 with ρm=7.9×103 kg m−3\rho_{\rm m}=7.9\times10^3\ \mathrm{kg\,m^{-3}}, a tension (a negative stress) along the wire, and no stress across it. This is not a perfect fluid, so the perfect-fluid forms of the energy conditions do not apply directly. Take c=3.00×108 m s−1c=3.00\times10^8\ \mathrm{m\,s^{-1}}. ((a)) An observer moves along the wire at speed vv. Boost TμνT^{\mu\nu} and find the energy density T′00T'^{00} this observer measures, in terms of ρ\rho, σ\sigma and β=v/c\beta=v/c. Say also what an observer moving across the wire, along yy, measures. ((b)) Using the weak energy condition in its general form, that every observer measures a non-negative energy density, find the condition on σ/ρ\sigma/\rho for the wire to satisfy it for every observer. Evaluate σ/ρ\sigma/\rho for the steel wire. ((c)) For a hypothetical material with the same ρ\rho, find the tension, as a multiple of ρ\rho, at which an observer moving along it at 0.6c0.6c would measure T′00=0T'^{00}=0, and say whether such a material satisfies the weak energy condition.

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