A geostationary communications satellite moves on a circular orbit of radius m…

PHYSICS · Multi-part · Fermi University Physics · Mechanics & Dynamical Systems · Relativity & Gravitation · The equivalence principle and gravity as geometry

The Geometry of Gravity, Ch Redshift, local inertial frames and the failure of flat spacetime

Problem

A geostationary communications satellite moves on a circular orbit of radius r=4.216×107r = 4.216\times10^{7} m (measured from the Earth's centre), so that its orbital speed satisfies v2=GM⊕/rv^2 = GM_\oplus/r. Ground clocks sit at radius R⊕=6.371×106R_\oplus = 6.371\times10^{6} m. Take GM⊕=3.986×1014 m3 s−2GM_\oplus = 3.986\times10^{14}\ \mathrm{m^3\,s^{-2}}. ((a)) Estimate the fractional rate difference contributed by height alone, GM⊕(1/R⊕−1/r)/c2GM_\oplus(1/R_\oplus - 1/r)/c^2, and convert it to microseconds gained per day. ((b)) Estimate the fractional rate difference contributed by orbital speed alone, −GM⊕/(2rc2)-GM_\oplus/(2rc^2), and convert it to microseconds per day. ((c)) Give the net daily offset of the satellite clock relative to a ground clock, and state whether the satellite runs fast or slow.

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