A cloud of non-interacting dust particles (pressureless fluid, ) has stress-energy tensor

PHYSICS · Multi-part · Fermi University Physics · Relativity & Gravitation · Differential geometry of curved spacetime · Differential geometry of curved spacetime

The Geometry of Gravity, Ch Matter in curved spacetime: minimal coupling and relativistic hydrodynamics

Problem

A cloud of non-interacting dust particles (pressureless fluid, p=0p=0) has stress-energy tensor Tμν=ρuμuνT^{\mu\nu}=\rho u^\mu u^\nu, with ρ\rho the rest-frame energy density and uμu^\mu the four-velocity of a fluid element, normalised by uμuμ=−1u_\mu u^\mu=-1. ((a)) Starting from ∇μTμν=0\nabla_\mu T^{\mu\nu}=0, contract with uνu_\nu and use uμuμ=−1u_\mu u^\mu=-1 to obtain the continuity equation ∇μ(ρuμ)=0\nabla_\mu(\rho u^\mu)=0. Substitute this back into ∇μTμν=0\nabla_\mu T^{\mu\nu}=0 to show that each dust element satisfies uμ∇μuν=0u^\mu\nabla_\mu u^\nu=0, the geodesic equation. ((b)) A weak, static, spherically symmetric gravitational field has the metric ds2=−(1+2Φc2)c2 dt2+dx2+dy2+dz2ds^2=-\left(1+\dfrac{2\Phi}{c^2}\right)c^2\,dt^2+dx^2+dy^2+dz^2, with ∣Φ/c2∣≪1|\Phi/c^2|\ll1 and Φ=Φ(x,y,z)\Phi=\Phi(x,y,z) time-independent (the Newtonian-limit metric). Using the definition of the Christoffel symbols, show that to leading order in Φ/c2\Phi/c^2, Γ 00i=∂iΦ\Gamma^i_{\ 00}=\partial_i\Phi. ((c)) A dust particle is instantaneously at rest in these coordinates, so uμ=(u0,0,0,0)u^\mu=(u^0,0,0,0) with u0=dt/dτ≈1u^0=dt/d\tau\approx1 for v≪cv\ll c. Write the spatial component of the geodesic equation for this particle and show it reduces to d2xidt2=−∂iΦ\dfrac{d^2x^i}{dt^2}=-\partial_i\Phi. ((d)) Take Φ(r)=−GM/r\Phi(r)=-GM/r, the potential of a point mass MM, and apply the result of part (c) at the surface of a body with M=1.99×1030 kgM=1.99\times10^{30}\ \mathrm{kg} and radius R=6.96×108 mR=6.96\times10^{8}\ \mathrm{m} (the Sun's mass and radius). Find the magnitude of the coordinate acceleration ∣d2xi/dt2∣|d^2x^i/dt^2| of a dust particle instantaneously at rest at that radius. Use G=6.674×10−11 N m2 kg−2G=6.674\times10^{-11}\ \mathrm{N\,m^2\,kg^{-2}}.

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