A timelike Killing vector of a static metric gives a conserved quantity along any…

PHYSICS · Multi-part · Fermi University Physics · Relativity & Gravitation · Differential geometry of curved spacetime · Schwarzschild spacetime and the tests of general relativity

The Geometry of Gravity, Ch The Schwarzschild geometry and Birkhoff's theorem

Problem

A timelike Killing vector ξμ=(∂t)μ\xi^\mu=(\partial_t)^\mu of a static metric gives a conserved quantity E=−gμνξμkνE=-g_{\mu\nu}\xi^\mu k^\nu along any geodesic with tangent kμk^\mu, timelike or null. The weak-field line element has gtt≈−(1−2GM/r~c2)c2g_{tt}\approx-(1-2GM/\tilde r c^2)c^2, with r~\tilde r the isotropic radial coordinate, and it was shown from the equivalence principle alone that a photon climbing from a static source at radius r1r_1 to a static receiver at radius r2>r1r_2>r_1 in a weak field is redshifted by z≈GM(1/r1−1/r2)/c2z\approx GM(1/r_1-1/r_2)/c^2. ((a)) For a metric of the static spherically symmetric ansatz, gtt=−e2A(r)g_{tt}=-e^{2\mathcal{A}(r)}, use the conservation of EE along a radial null geodesic, together with the fact that a static metric's components do not depend on tt, to write the ratio ν2/ν1\nu_2/\nu_1 of received to emitted frequency in terms of eAe^{\mathcal{A}} at r1r_1 and r2r_2. ((b)) Match e2Ae^{2\mathcal{A}} at large rr to the weak-field form to identify the integration constant of the vacuum solution as 2GM/c22GM/c^2, and show that the ratio found in part (a) reduces, to first order in GM/rc2GM/rc^2, to the equivalence-principle redshift formula above. ((c)) A photon leaves the surface of the Earth (R⊕=6371R_\oplus=6371 km, GM⊕/c2=4.44GM_\oplus/c^2=4.44 mm) and is received by an observer at rest very far away (r2→∞r_2\to\infty). Evaluate the first-order redshift zz numerically.

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