Earth's orbit has mean orbital speed m s at mean distance m from the Sun ( m s );…

PHYSICS · Multi-part · Fermi University Physics · Relativity & Gravitation · Schwarzschild spacetime and the tests of general relativity · Schwarzschild spacetime and the tests of general relativity

The Geometry of Gravity, Ch Orbits and light rays in Schwarzschild spacetime

Problem

Earth's orbit has mean orbital speed v=2.978×104v = 2.978\times10^4 m s−1^{-1} at mean distance r=1.496×1011r = 1.496\times10^{11} m from the Sun (GM⊙=1.327×1020GM_\odot = 1.327\times10^{20} m3^3 s−2^{-2}); treat the orbit as circular for this problem. ((a)) Starting from the timelike radial equation c2E2=(1−rs/r)(c2+L2/r2)c^2E^2 = (1-r_s/r)(c^2+L^2/r^2) (with r˙=0\dot r=0 for a circular orbit), and using the Newtonian circular-orbit relation L2/r2=v2=GM/rL^2/r^2 = v^2 = GM/r, expand EE to first order in GM/rc2GM/rc^2 and v2/c2v^2/c^2 and show it reduces to E≈1−GM/2rc2E \approx 1 - GM/2rc^2. ((b)) Evaluate E−1E-1 numerically for Earth's orbit. ((c)) The weak-field metric has g00=−(1+2Φ/c2)g_{00} = -(1+2\Phi/c^2) with Φ=−GM/r\Phi=-GM/r, the same g00g_{00} used here to leading order. Using the equivalence-principle-test logic that any metric theory reproducing the measured redshift shares this g00g_{00}, and Birkhoff's theorem that the Schwarzschild metric is the unique vacuum solution of the full field equations, explain why matching EE to the Newtonian energy in this way tests only the weak-field limit shared by many metric theories, and not the field equations themselves, in contrast with the perihelion advance.

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