The Schwarzschild radial equation for a bound timelike orbit

PHYSICS · Multi-part · Fermi University Physics · Mechanics & Dynamical Systems · Relativity & Gravitation · Gravitation and central-force motion

The Geometry of Gravity, Ch Orbits and light rays in Schwarzschild spacetime

Problem

The Schwarzschild radial equation for a bound timelike orbit, written in terms of u≡1/ru\equiv1/r and ϕ\phi, is u′′+u=GML2+3GMc2u2,u''+u=\frac{GM}{L^2}+\frac{3GM}{c^2}u^2, primes denoting d/dϕd/d\phi, where LL is the angular momentum per unit rest mass. ((a)) Solve this equation to first order in GM/rc2GM/rc^2, treating the last term as a small perturbation on the Newtonian ellipse u0=(GM/L2)(1+ecos⁡ϕ)u_0=(GM/L^2)(1+e\cos\phi). Show that the perihelion of the orbit advances by Δϖ=6πGM/(c2a(1−e2))\Delta\varpi=6\pi GM/\big(c^2a(1-e^2)\big) per orbit, with aa the semi-major axis and ee the eccentricity. ((b)) The binary pulsar PSR B1913+16 (the Hulse–Taylor pulsar) has orbital period Torb=7.751T_{\rm orb}=7.751 h, eccentricity e=0.617e=0.617 and total mass (both neutron stars together) M=2.828 M⊙M=2.828\,M_\odot. Using Kepler's third law for the relative orbit, a3=GMTorb2/4π2a^3=GMT_{\rm orb}^2/4\pi^2, find the semi-major axis aa, and hence the periastron advance rate in degrees per year, using GM⊙/c2=1.48GM_\odot/c^2=1.48 km. Compare with the measured rate of 4.226 ∘ yr−14.226\ ^\circ\,{\rm yr}^{-1}.

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