A point mass at distance from an observer bends a light ray from a background source…

PHYSICS · Multi-part · Fermi University Physics · Relativity & Gravitation · Schwarzschild spacetime and the tests of general relativity · Schwarzschild spacetime and the tests of general relativity

The Geometry of Gravity, Ch Orbits and light rays in Schwarzschild spacetime

Problem

A point mass MM at distance DLD_{\rm L} from an observer bends a light ray from a background source at distance DSD_{\rm S} (with DLSD_{\rm LS} the distance from lens to source) by the angle Δϕ=4GM/(bc2)\Delta\phi=4GM/(bc^2), where bb is the impact parameter of the ray at the lens. All angles are small, and DLD_{\rm L}, DSD_{\rm S} and DLSD_{\rm LS} are treated as ordinary Euclidean distances. ((a)) Using the small-angle relation b=DLθIb=D_{\rm L}\theta_{\rm I}, where θI\theta_{\rm I} is the angle at which the image is seen, and the lens equation θS=θI−(DLS/DS)Δϕ\theta_{\rm S}=\theta_{\rm I}-(D_{\rm LS}/D_{\rm S})\Delta\phi relating the source angle θS\theta_{\rm S} to θI\theta_{\rm I}, derive the Einstein ring radius θE=4GMc2 DLSDLDS,\theta_{\rm E}=\sqrt{\frac{4GM}{c^2}\,\frac{D_{\rm LS}}{D_{\rm L}D_{\rm S}}}, the value of θI\theta_{\rm I} when the source lies exactly behind the lens (θS=0\theta_{\rm S}=0). ((b)) A red dwarf of mass 0.30 M⊙0.30\,M_\odot lies at distance DL=4.0D_{\rm L}=4.0 kpc and lenses a background star at distance DS=8.0D_{\rm S}=8.0 kpc, with DLS≈DS−DL=4.0D_{\rm LS}\approx D_{\rm S}-D_{\rm L}=4.0 kpc. Using GM⊙/c2=1.48GM_\odot/c^2=1.48 km and 1 pc=3.086×10161\ {\rm pc}=3.086\times10^{16} m, find θE\theta_{\rm E} in milliarcseconds.

Browse the problem library