The deuteron's measured spectroscopic quadrupole moment is

PHYSICS · Multi-part · Fermi University Physics · Quantum Mechanics · Nuclear Physics · The nuclear force and nuclear models

The Nucleus Resolved, Ch The deuteron and what two nucleons do to each other

Problem

The deuteron's measured spectroscopic quadrupole moment is Qsp=+0.286 fm2Q_{sp}=+0.286\,\mathrm{fm^2}, definitely not zero, even though its dominant component is the ℓ=0\ell=0 3S1^3S_1 state. Write the deuteron's quadrupole moment as Qsp=(1−PD)QS+PDQD+2PD(1−PD) QSD,Q_{sp}=(1-P_D)Q_S+P_DQ_D+2\sqrt{P_D(1-P_D)}\,Q_{SD}, where QSQ_S, QDQ_D and QSDQ_{SD} are, respectively, the quadrupole moment of the pure 3S1^3S_1 state, of the pure 3D1^3D_1 state, and the 3S1^3S_1-3D1^3D_1 interference matrix element, and PDP_D is the DD-state probability. A particular model of the deuteron's radial wavefunctions gives the interference matrix element QSD=0.65 fm2Q_{SD}=0.65\,\mathrm{fm^2}; the pure DD-state term is small enough to be dropped at the level of this estimate. ((a)) State the value of QSQ_S and justify it. ((b)) Show that, for a small admixture, Qsp≈2PD QSDQ_{sp}\approx2\sqrt{P_D}\,Q_{SD}, and explain in one sentence which operator property makes the interference term, not the population term, the leading one. ((c)) Use the measured QspQ_{sp} and the given QSDQ_{SD} to estimate PDP_D, and check that the smallness assumed in part (b) is satisfied.

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