A simplified mean-field model represents a light

PHYSICS · Multi-part · Fermi University Physics · Nuclear Physics · The nuclear force and nuclear models · The nuclear force and nuclear models

The Nucleus Resolved, Ch The shell model: a mean field, a spin-orbit term and the magic numbers

Problem

A simplified mean-field model represents a light, closed-orbital nucleus as AA identical nucleons occupying a single filled orbital. Each nucleon has the same kinetic energy tt, and every one of the (A2)\binom{A}{2} distinct pairs of nucleons shares the same average two-body interaction energy vˉ\bar v (attractive, so vˉ<0\bar v < 0). In the mean-field picture each nucleon moves in the field produced by the other A−1A-1 nucleons, so its single-particle energy is ϵ=t+(A−1)vˉ.\epsilon = t + (A-1)\bar v. ((a)) Write the total energy EE of the AA-nucleon system as the sum of the kinetic energies plus the sum over distinct pairs, and show that E=A2(ϵ+t)E = \dfrac{A}{2}(\epsilon+t). ((b)) Show that summing the single-particle energies, AϵA\epsilon, double-counts the pairwise interaction energy, by comparing Aϵ−AtA\epsilon - At with the true total interaction energy E−AtE-At. ((c)) For a nucleus with A=10A=10 nucleons in this model, separation-energy data give a single-particle energy ϵ=−20.0 MeV\epsilon = -20.0\,\mathrm{MeV}, and a Fermi-gas estimate of the mean kinetic energy per nucleon gives t=10.0 MeVt = 10.0\,\mathrm{MeV}. Use the result of part (a) to estimate the binding energy B=−EB=-E, and state by what factor ∣Aϵ∣|A\epsilon| overestimates BB.

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