Over the range -

PHYSICS · Multi-part · Fermi University Physics · Nuclear Physics · Radiation interactions, detection and dosimetry · Radiation interactions, detection and dosimetry

The Nucleus Resolved, Ch Radiation in matter, computed: Bethe, Klein-Nishina and what they leave out

Problem

Over the range 100100-200 MeV200\,\mathrm{MeV}, the Bethe-formula range of a proton in water is well fitted by a power law R=αEp,p=1.75,R = \alpha E^{p}, \qquad p = 1.75, with RR in g cm−2\mathrm{g\,cm^{-2}} and EE in MeV\mathrm{MeV}. The integral of the reciprocal stopping power gives R(100 MeV)=7.71 g cm−2R(100\,\mathrm{MeV}) = 7.71\,\mathrm{g\,cm^{-2}} and R(200 MeV)=25.95 g cm−2R(200\,\mathrm{MeV}) = 25.95\,\mathrm{g\,cm^{-2}}. The density of water is 1.00 g cm−31.00\,\mathrm{g\,cm^{-3}}. ((a)) Use the 100 MeV100\,\mathrm{MeV} point to find α\alpha, and check it against the 200 MeV200\,\mathrm{MeV} point. ((b)) Find the range in water of a 150 MeV150\,\mathrm{MeV} proton, in centimetres.

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