A beam bombards a target at a centre-of-mass energy

PHYSICS · Multi-part · Fermi University Physics · Nuclear Physics · Nuclear reactions · Nuclear reactions

The Nucleus Resolved, Ch Beams and the edges of the chart: emittance, heavy ions, high spin and the drip lines

Problem

A 58Ni^{58}\mathrm{Ni} beam bombards a 58Ni^{58}\mathrm{Ni} target at a centre-of-mass energy Ecm=200 MeVE_{\rm cm} = 200\,\mathrm{MeV}. Someone argues: 'The Coulomb barrier for this pair is only about 110 MeV110\,\mathrm{MeV}, and 200 MeV200\,\mathrm{MeV} is well above it, so essentially every collision has enough energy to overcome the barrier and fuse into a single compound nucleus.' ((a)) Using R=1.3(A11/3+A21/3) fmR=1.3(A_1^{1/3}+A_2^{1/3})\,\mathrm{fm} and μred=A1A2A1+A2 u\mu_{\rm red}=\dfrac{A_1A_2}{A_1+A_2}\,\mathrm{u}, compute BCB_C and the grazing angular momentum ℓgr=R2μred(Ecm−BC)/ℏ\ell_{\rm gr} = R\sqrt{2\mu_{\rm red}(E_{\rm cm}-B_C)}/\hbar (with μred\mu_{\rm red} expressed as an energy μredc2\mu_{\rm red}c^2). ((b)) Given that the highest spins seen in any discrete rotational band are of order 60ℏ60\hbar, explain why the argument above is wrong, and say which impact parameters (small or large, i.e. small or large orbital angular momentum) actually lead to fusion-evaporation residues at this energy.

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