A shape isomer of sits above the ground state

PHYSICS · Multi-part · Fermi University Physics · Quantum Mechanics · Nuclear Physics · Fission, fusion and nuclear energy

The Nucleus Resolved, Ch Fission: the double-humped barrier and the shells the drop cannot see

Problem

A shape isomer of 242Am^{242}\mathrm{Am} sits 2.3 MeV2.3\,\mathrm{MeV} above the ground state, trapped in the second minimum of the double-humped barrier. The top of the outer barrier lies Eb=3.4 MeVE_b = 3.4\,\mathrm{MeV} above this isomeric state. Model the second well as a parabola with curvature ℏωII=0.80 MeV\hbar\omega_{II} = 0.80\,\mathrm{MeV} and the outer barrier as a parabola with curvature ℏωB\hbar\omega_B. Carry over the parabolic-barrier WKB penetrability, P≈exp⁡(−2πEb/ℏωB)P \approx \exp(-2\pi E_b/\hbar\omega_B), and the assault-frequency estimate ν=ℏωII/h\nu = \hbar\omega_{II}/h (with h=2πℏh = 2\pi\hbar) to estimate the fission decay constant λf=νP\lambda_f = \nu P and hence the half-life T1/2=ln⁡2/λfT_{1/2} = \ln 2/\lambda_f. ((a)) Estimate T1/2T_{1/2} for ℏωB=0.50 MeV\hbar\omega_B = 0.50\,\mathrm{MeV}. ((b)) Repeat for ℏωB=0.45 MeV\hbar\omega_B = 0.45\,\mathrm{MeV}, all else unchanged, and state by what factor the half-life has moved.

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