An electron of mass is confined to an infinite square well of width

PHYSICS · Multi-part · Fermi University Physics · Quantum Mechanics · Wave mechanics in one dimension · Quantum dynamics and its formulations

The Structure of Quantum Mechanics, Ch The wave function is not the state

Problem

An electron of mass m=9.11×10−31 kgm = 9.11\times10^{-31}\,\mathrm{kg} is confined to an infinite square well of width L=1.20 nmL = 1.20\,\mathrm{nm}, with normalised eigenfunctions ψn(x)=2/Lsin⁡(nπx/L)\psi_n(x) = \sqrt{2/L}\sin(n\pi x/L) and energies En=n2π2ℏ2/(2mL2)E_n = n^2\pi^2\hbar^2/(2mL^2). At t=0t=0 the state is prepared as Ψ(x,0)=12[ψ2(x)+ψ3(x)].\Psi(x,0) = \frac{1}{\sqrt2}\big[\psi_2(x) + \psi_3(x)\big]. ((a)) Working in the energy description (the list of amplitudes cnc_n), give P(E2)P(E_2) and P(E3)P(E_3). ((b)) From the energy list, give the numerical value of E3−E2E_3 - E_2 in joules, and hence the beat angular frequency ω32=(E3−E2)/ℏ\omega_{32} = (E_3-E_2)/\hbar at which the position density oscillates. ((c)) Evaluate the position probability density ∣Ψ(x,0)∣2|\Psi(x,0)|^2 at x=L/2x = L/2, using the position description directly, and check that it equals ∣c3∣2∣ψ3(L/2)∣2|c_3|^2|\psi_3(L/2)|^2, saying why c2c_2 contributes nothing at this point.

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