An electron ( ) is confined to an infinite square well of width

PHYSICS · Subjective · Fermi University Physics · Quantum Mechanics · Wave mechanics in one dimension · Quantum dynamics and its formulations

The Structure of Quantum Mechanics, Ch The wave function is not the state

Problem

An electron (m=9.11×10−31 kgm=9.11\times10^{-31}\,\mathrm{kg}) is confined to an infinite square well of width L=0.80 nmL=0.80\,\mathrm{nm}, with ψn(x)=2/Lsin⁡(nπx/L)\psi_n(x)=\sqrt{2/L}\sin(n\pi x/L) and En=n2π2ℏ2/(2mL2)E_n=n^2\pi^2\hbar^2/(2mL^2). At t=0t=0 it is prepared in Ψ(x,0)=[ψ1(x)+ψ2(x)]/2\Psi(x,0)=\big[\psi_1(x)+\psi_2(x)\big]/\sqrt2. (a) Using cn(t)=cn(0)e−iEnt/ℏc_n(t)=c_n(0)e^{-iE_nt/\hbar}, write Ψ(x,t)\Psi(x,t) as a global phase times [ψ1(x)+eiα(t)ψ2(x)]/2\big[\psi_1(x)+e^{i\alpha(t)}\psi_2(x)\big]/\sqrt2, and identify α(t)\alpha(t). (b) Using ψ1(L−x)=ψ1(x)\psi_1(L-x)=\psi_1(x) and ψ2(L−x)=−ψ2(x)\psi_2(L-x)=-\psi_2(x), find the first time t∗>0t^*>0 at which ∣Ψ(x,t)∣2|\Psi(x,t)|^2 is the mirror image of ∣Ψ(x,0)∣2|\Psi(x,0)|^2 about x=L/2x=L/2, and evaluate t∗t^* in femtoseconds. (c) Prepare instead [ψ1(x)+ψ3(x)]/2\big[\psi_1(x)+\psi_3(x)\big]/\sqrt2. Show that its density is symmetric about x=L/2x=L/2 at every time, and find ∣Ψ(L/2,t)∣2|\Psi(L/2,t)|^2 to show that the density nonetheless changes.

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