A three-level system has an orthonormal basis

PHYSICS · Multi-part · Fermi University Physics · Quantum Mechanics · The formalism of quantum mechanics · The formalism of quantum mechanics

The Structure of Quantum Mechanics, Ch Compatible observables and uncertainty as a theorem

Problem

A three-level system has an orthonormal basis {∣1⟩,∣2⟩,∣3⟩}\{|1\rangle,|2\rangle,|3\rangle\}. In this basis, three self-adjoint operators are represented by A^=(100010002),B^=(010100003),C^=(0i0−i00004).\hat A = \begin{pmatrix}1&0&0\\0&1&0\\0&0&2\end{pmatrix}, \qquad \hat B = \begin{pmatrix}0&1&0\\1&0&0\\0&0&3\end{pmatrix}, \qquad \hat C = \begin{pmatrix}0&i&0\\-i&0&0\\0&0&4\end{pmatrix}. ((a)) Compute [A^,B^][\hat A,\hat B] and [A^,C^][\hat A,\hat C]. State exactly what the compatibility theorem then guarantees about a common eigenbasis for A^\hat A with B^\hat B, and separately for A^\hat A with C^\hat C. ((b)) Find the common eigenbasis of A^\hat A and B^\hat B explicitly, by diagonalising B^\hat B within the two-dimensional eigenspace of A^\hat A where A^\hat A is degenerate. Give each basis vector's pair of eigenvalues (a,b)(a,b). ((c)) Compute [B^,C^][\hat B,\hat C]. Decide, from this commutator alone, whether measuring B^\hat B then C^\hat C on a general state of the system gives the same statistics as measuring C^\hat C then B^\hat B. ((d)) Reconcile parts (a) and (c): explain why B^\hat B and C^\hat C each being compatible with A^\hat A does not make B^\hat B and C^\hat C compatible with each other.

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