A three-dimensional state space has an orthonormal basis that is a common eigenbasis…

PHYSICS · Multi-part · Fermi University Physics · Quantum Mechanics · The formalism of quantum mechanics · The formalism of quantum mechanics

The Structure of Quantum Mechanics, Ch Compatible observables and uncertainty as a theorem

Problem

A three-dimensional state space has an orthonormal basis {∣1⟩,∣2⟩,∣3⟩}\{|1\rangle,|2\rangle,|3\rangle\} that is a common eigenbasis of two self-adjoint operators A^\hat A and B^\hat B: A^∣n⟩=an∣n⟩\hat A|n\rangle=a_n|n\rangle, B^∣n⟩=bn∣n⟩\hat B|n\rangle=b_n|n\rangle, with (a1,a2,a3)=(1,1,2) ε0(a_1,a_2,a_3)=(1,1,2)\,\varepsilon_0 and (b1,b2,b3)=(5,3,3) μ0(b_1,b_2,b_3)=(5,3,3)\,\mu_0, where ε0,μ0\varepsilon_0,\mu_0 are constants carrying the appropriate units. A function of an operator means f(A^)=∑af(a)P^af(\hat A)=\sum_a f(a)\hat P_a, as in Chapter 3. ((a)) Show that neither {A^}\{\hat A\} nor {B^}\{\hat B\} alone is a complete set of commuting observables, but {A^,B^}\{\hat A,\hat B\} is. ((b)) Show that B^\hat B cannot be written as f(A^)f(\hat A) for any function ff, and that A^\hat A cannot be written as g(B^)g(\hat B) for any function gg. ((c)) Let C^=A^/ε0+B^/μ0\hat C=\hat A/\varepsilon_0+\hat B/\mu_0. Show that {C^}\{\hat C\} alone is a complete set of commuting observables, and find polynomials ff and gg, each of degree at most 2, with A^=ε0f(C^)\hat A=\varepsilon_0 f(\hat C) and B^=μ0g(C^)\hat B=\mu_0 g(\hat C). ((d)) Explain why part (c) does not contradict part (b).

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