An electron's state is the (improper

PHYSICS · Multi-part · Fermi University Physics · Quantum Mechanics · The formalism of quantum mechanics · The formalism of quantum mechanics

The Structure of Quantum Mechanics, Ch Position, momentum and the origin of the canonical commutator

Problem

An electron's state is the (improper, delta-normalised) momentum eigenstate φp0(x)=⟨x∣p0⟩=12πℏ eip0x/ℏ,\varphi_{p_0}(x) = \langle x|p_0\rangle = \dfrac{1}{\sqrt{2\pi\hbar}}\,e^{ip_0x/\hbar}, with p0=h/λp_0 = h/\lambda for a de Broglie wavelength λ=0.40\lambda = 0.40 nm. ((a)) Using ⟨x∣T^(a)∣φp0⟩=φp0(x−a)\langle x|\hat T(a)|\varphi_{p_0}\rangle = \varphi_{p_0}(x-a), show that ∣p0⟩|p_0\rangle is an eigenvector of T^(a)\hat T(a), and find its eigenvalue for a translation a=0.10a=0.10 nm. ((b)) Give the phase angle of this eigenvalue in radians, and confirm that its modulus is 11. ((c)) Explain in one sentence what this modulus tells about the probability density ∣φp0(x)∣2|\varphi_{p_0}(x)|^2 under translation.

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