An electron near the bottom of a conduction band is often modelled with a…

PHYSICS · Multi-part · Fermi University Physics · Quantum Mechanics · The formalism of quantum mechanics · The formalism of quantum mechanics

The Structure of Quantum Mechanics, Ch Position, momentum and the origin of the canonical commutator

Problem

An electron near the bottom of a conduction band is often modelled with a position-dependent effective mass m(x)m(x), with classical Hamiltonian H=p22m(x)H = \dfrac{p^2}{2m(x)}. Take the simple case m(x)=m0(1+xL)m(x) = m_0\left(1+\dfrac{x}{L}\right) for a length scale LL, and quantise to leading order in x/Lx/L with the symmetrised ordering, so that H^≈p^22m0−14m0L(x^p^2+p^2x^)\hat H \approx \dfrac{\hat p^2}{2m_0} - \dfrac{1}{4m_0 L}\big(\hat x\hat p^2+\hat p^2\hat x\big), which is Hermitian.A study group argues: "the canonical commutator [x^,p^]=iℏ[\hat x,\hat p]=i\hbar holds no matter how we order x^\hat x and p^\hat p when we build H^\hat H, so the ordering choice cannot affect whether p^\hat p is conserved; since [x^,p^][\hat x,\hat p] is fixed, [H^,p^]=0[\hat H,\hat p]=0 regardless of the ordering, exactly as for a free particle." ((a)) Compute [H^,p^][\hat H,\hat p] for the stated ordering and say whether it is zero. ((b)) Explain the logical error in the study group's reasoning, referring to what actually controls whether a Hamiltonian commutes with the generator of translations.

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