A particle of mass (an electron) sits in a one-dimensional harmonic trap of angular…

PHYSICS · Multi-part · Fermi University Physics · Quantum Mechanics · Wave mechanics in one dimension · Quantum dynamics and its formulations

The Structure of Quantum Mechanics, Ch The oscillator as an algebra

Problem

A particle of mass m=9.11×10−31 kgm=9.11\times10^{-31}\,\text{kg} (an electron) sits in a one-dimensional harmonic trap of angular frequency ω=2.00×1014 rad s−1\omega=2.00\times10^{14}\,\text{rad s}^{-1}, so that with no extra force H^0=ℏω(a^†a^+12)\hat H_0=\hbar\omega(\hat a^\dagger\hat a+\tfrac12) with the usual x^=ℏ/2mω (a^+a^†)\hat x=\sqrt{\hbar/2m\omega}\,(\hat a+\hat a^\dagger). A uniform force F=5.00×10−12 NF=5.00\times10^{-12}\,\text{N} (for instance from a uniform electric field acting on the electron's charge) is then switched on, so the full Hamiltonian is H^=ℏω(a^†a^+12)−Fx^\hat H=\hbar\omega(\hat a^\dagger\hat a+\tfrac12)-F\hat x. ((a)) Show that defining b^=a^−λ\hat b=\hat a-\lambda for a suitably chosen real number λ\lambda turns H^\hat H into ℏω(b^†b^+12)+constant\hbar\omega(\hat b^\dagger\hat b+\tfrac12)+\text{constant}, with [b^,b^†]=1[\hat b,\hat b^\dagger]=1 unchanged. Give λ\lambda and the resulting energy levels EnE_n in terms of FF, mm, ω\omega, ℏ\hbar and the integer n=0,1,2,…n=0,1,2,\dots ((b)) Evaluate E0E_0 and E1E_1 numerically, in electronvolts. ((c)) Write x^\hat x as ℏ/2mω (b^+b^†)\sqrt{\hbar/2m\omega}\,(\hat b+\hat b^\dagger) plus a constant, and find the constant. The ladder part b^+b^†\hat b+\hat b^\dagger obeys the same selection rule as a^+a^†\hat a+\hat a^\dagger: its matrix elements between the number states ∣n⟩b|n\rangle_b of b^†b^\hat b^\dagger\hat b are nonzero only when the b^\hat b-numbers differ by exactly one. Use this to show that ⟨n∣b x^ ∣n⟩b\langle n|_b\,\hat x\,|n\rangle_b is the same for every nn, evaluate it numerically in nanometres, and compare it with the classical equilibrium position where d/dx[12mω2x2−Fx]=0d/dx\left[\tfrac12 m\omega^2x^2-Fx\right]=0.

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