A single unpaired electron (spin one-half) is bound at a lattice site of a crystal…

PHYSICS · Multi-part · Fermi University Physics · Quantum Mechanics · Symmetry, angular momentum and spin · Symmetry, angular momentum and spin

The Structure of Quantum Mechanics, Ch Symmetries, generators and conservation laws

Problem

A single unpaired electron (spin one-half) is bound at a lattice site of a crystal whose local electric field has no rotational, reflection or inversion symmetry at all: a generic low-symmetry site described by a real, time-independent potential energy V(r⃗)V(\vec r) that does not commute with any component of orbital angular momentum. There is no external magnetic field and no spin-orbit term, so H^=p^22m+V(r⃗^)\hat H=\dfrac{\hat p^2}{2m}+V(\hat{\vec r}) acts only on the orbital motion, with the spin degree of freedom present but absent from H^\hat H. ((a)) Explain why time reversal Θ^\hat\Theta commutes with this H^\hat H even though V(r⃗)V(\vec r) has no spatial symmetry at all. ((b)) For spin one-half, Θ^2=−1\hat\Theta^2=-1. Starting from ⟨Θ^ψ∣Θ^2ψ⟩=⟨Θ^ψ∣ψ⟩\langle\hat\Theta\psi|\hat\Theta^2\psi\rangle=\langle\hat\Theta\psi|\psi\rangle and the antiunitary identity ⟨Θ^ϕ∣Θ^χ⟩=⟨χ∣ϕ⟩\langle\hat\Theta\phi|\hat\Theta\chi\rangle=\langle\chi|\phi\rangle, show that ⟨Θ^ψ∣ψ⟩=0\langle\hat\Theta\psi|\psi\rangle=0, and deduce that ∣ψ⟩|\psi\rangle and ∣ψ~⟩≡Θ^∣ψ⟩|\tilde\psi\rangle\equiv\hat\Theta|\psi\rangle are linearly independent. ((c)) Given [H^,Θ^]=0[\hat H,\hat\Theta]=0, show that ∣ψ~⟩|\tilde\psi\rangle has the same energy as ∣ψ⟩|\psi\rangle, and conclude what this means for the degeneracy of every level of this electron, however asymmetric the crystal field, and what alone can lift it.

Related theory

Browse the problem library