Two electrons occupy a orbital ( ) and a orbital ( )

PHYSICS · Subjective · Fermi University Physics · Quantum Mechanics · Symmetry, angular momentum and spin · Symmetry, angular momentum and spin

The Structure of Quantum Mechanics, Ch Adding angular momenta, tensor operators and Wigner-Eckart

Problem

Two electrons occupy a dd orbital (l1=2l_1=2) and a pp orbital (l2=1l_2=1). Consider only their orbital angular momenta, in the uncoupled basis ∣m1⟩∣m2⟩|m_1\rangle|m_2\rangle (m1=2,1,0,−1,−2m_1=2,1,0,-1,-2; m2=1,0,−1m_2=1,0,-1) and the coupled basis ∣J,M⟩|J,M\rangle, together with J^−∣j,m⟩=ℏj(j+1)−m(m−1) ∣j,m−1⟩\hat J_-|j,m\rangle=\hbar\sqrt{j(j+1)-m(m-1)}\,|j,m-1\rangle and J^−=J^1−+J^2−\hat J_-=\hat J_{1-}+\hat J_{2-}. (a) Tabulate M=m1+m2M=m_1+m_2 over all fifteen product states, peel off multiplets from the top, and derive l1⊗l2=⨁JJl_1\otimes l_2=\bigoplus_J J. Check the dimension count. (b) Lower the unique top state ∣J=3,M=3⟩=∣m1=2⟩∣m2=1⟩|J=3,M=3\rangle=|m_1=2\rangle|m_2=1\rangle once to obtain ∣3,2⟩|3,2\rangle. Use orthogonality inside the two-dimensional M=2M=2 subspace, with the Condon-Shortley sign fixed by requiring the coefficient of ∣m1=2⟩∣m2=0⟩|m_1=2\rangle|m_2=0\rangle to be positive, to construct the top state ∣J=2,M=2⟩|J=2,M=2\rangle of the next multiplet.

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