Doubly-ionised lithium, Li

PHYSICS · Multi-part · Fermi University Physics · Quantum Mechanics · Central potentials and canonical three-dimensional systems · Approximation methods

The Structure of Quantum Mechanics, Ch Hydrogen, and the symmetry that explains it

Problem

Doubly-ionised lithium, Li2+^{2+}, has a single electron bound to a nucleus of charge ZeZe with Z=3Z=3 by the Coulomb potential V(r)=−Ze24πϵ0rV(r)=-\dfrac{Ze^2}{4\pi\epsilon_0 r}. The SO(4)SO(4) result derived for hydrogen holds for any such one-electron, one-over-rr system once ZZ is inserted. Consider the n=4n=4 level. ((a)) State the energy E4E_4 (in eV, to four significant figures) from the Casimir relation, and give the total number of degenerate spatial states and the allowed orbital quantum numbers ll with their degeneracies 2l+12l+1. ((b)) A weak uniform electric field E⃗=Ez^\vec E = E\hat z is switched on, adding H^′=eEz^\hat H' = eE\hat z to the Hamiltonian. This operator commutes with L^z\hat L_z but is odd under the parity operator Π^\hat\Pi. For each value of mm from −3-3 to 33, state how many of the 1616 degenerate n=4n=4 states carry that value of mm; this is the size of the subspace that must be diagonalised to find the energy shifts linear in EE for that mm. State which value(s) of ∣m∣|m| give a one-dimensional subspace, and explain why no state in such a subspace can show a shift linear in EE. Do not compute the size of any shift.

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