Someone argues: “The velocity of a charged particle equals

PHYSICS · Subjective · Fermi University Physics · Quantum Mechanics · The formalism of quantum mechanics · The formalism of quantum mechanics

The Structure of Quantum Mechanics, Ch Charged particles in electromagnetic fields

Problem

Someone argues: “The velocity of a charged particle equals p⃗^/m\hat{\vec p}/m, because p⃗^\hat{\vec p} is the generator of translations exactly as for a free particle. By the canonical commutation relations, [p^x,p^y]=0[\hat p_x,\hat p_y]=0 always, whatever fields are present, so the two velocity components commute and can in principle both be measured to arbitrary precision, magnetic field or not.” Find the error(s) in this argument, and give the correct commutator [v^x,v^y][\hat v_x,\hat v_y] for a particle of charge qq and mass mm in a uniform field B⃗=Bz^\vec B=B\hat z.

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