A rigid cubical vessel of side holds nitrogen

PHYSICS · Multi-part · Fermi University Physics · Thermal, Statistical & Complex Systems · Kinetic theory and transport in gases · Kinetic theory and transport in gases

Thermal Physics, Ch Temperature, pressure and the kinetic theory of gases

Problem

A rigid cubical vessel of side aa holds nitrogen, treated as an ideal gas of point molecules of mass m=4.65×10−26 kgm = 4.65\times10^{-26}\,\mathrm{kg} that bounce elastically off the rigid walls. Gravity is ignored and the velocity distribution is isotropic and unchanging. The number density is n=N/V=2.0×1025 m−3n = N/V = 2.0\times10^{25}\,\mathrm{m^{-3}} and the temperature is 350 K350\,\mathrm{K}. ((a)) Starting from a single molecule bouncing between two opposite walls, derive p=13nm⟨v2⟩p = \tfrac13 nm\langle v^2\rangle, naming the one assumption you use about the components of velocity. ((b)) Taking the speed distribution f(v)=4π(m2πkBT)3/2v2e−mv2/2kBTf(v) = 4\pi\left(\dfrac{m}{2\pi k_BT}\right)^{3/2}v^2e^{-mv^2/2k_BT} as given, use the Gaussian integral ∫−∞∞e−αx2 dx=π/α\int_{-\infty}^{\infty}e^{-\alpha x^2}\,\mathrm{d}x = \sqrt{\pi/\alpha} and differentiation with respect to α\alpha to show that ⟨v2⟩=3kBT/m\langle v^2\rangle = 3k_BT/m, and hence that the wall-collision result becomes pV=NkBTpV = Nk_BT. ((c)) Evaluate vrmsv_{\rm rms} and pp for this sample.

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