Two glass bulbs are joined by a narrow vertical pipe of negligible volume fitted with…

PHYSICS · Multi-part · Fermi University Physics · Thermal, Statistical & Complex Systems · Thermodynamic potentials and the formal structure of thermodynamics · Thermodynamic potentials and the formal structure of thermodynamics

Thermal Physics, Ch Chemical potential, open systems and chemical equilibrium

Problem

Two glass bulbs are joined by a narrow vertical pipe of negligible volume fitted with a closed valve. The lower bulb sits at z=0z = 0 on a mountainside, the upper bulb at z=1200 mz = 1200\,\mathrm{m}. Both contain nitrogen, treated as an ideal gas, and both are held at T=290 KT = 290\,\mathrm{K} throughout. The number densities are nlow=2.50×1025 m−3n_{\rm low} = 2.50\times10^{25}\,\mathrm{m^{-3}} in the lower bulb and nup=2.30×1025 m−3n_{\rm up} = 2.30\times10^{25}\,\mathrm{m^{-3}} in the upper one. At the common temperature the chemical potential of the gas in a bulb at height zz may be written μ=kBTln⁡(n/n0)+μ0′(T)+mgz\mu = k_BT\ln(n/n_0) + \mu_0'(T) + mgz, with nn the number density and n0n_0 any fixed reference density. Molar mass of nitrogen 28.0 g mol−128.0\,\mathrm{g\,mol^{-1}}; g=9.81 m s−2g = 9.81\,\mathrm{m\,s^{-2}}, NA=6.022×1023 mol−1N_A = 6.022\times10^{23}\,\mathrm{mol^{-1}}, kB=1.381×10−23 J K−1k_B = 1.381\times10^{-23}\,\mathrm{J\,K^{-1}}. ((a)) Compute Δμ=μup−μlow\Delta\mu = \mu_{\rm up} - \mu_{\rm low} per molecule for the gas as it stands. From its sign, say which way molecules move when the valve is opened (a positive value means the upper bulb has the higher chemical potential). ((b)) Find the ratio nup/nlown_{\rm up}/n_{\rm low} at which the valve could be opened with no net flow at all.

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