Sodium vapour (monatomic, ) is treated as a classical ideal gas at

PHYSICS · Multi-part · Fermi University Physics · Thermal, Statistical & Complex Systems · Thermodynamic potentials and the formal structure of thermodynamics · Statistical mechanics of ideal classical systems

Thermal Physics, Ch The classical ideal gas from the partition function

Problem

Sodium vapour (monatomic, M=22.99 g mol−1M = 22.99\,\mathrm{g\,mol^{-1}}) is treated as a classical ideal gas at T=1000 KT = 1000\,\mathrm{K}. Chapter 8 wrote the chemical potential of an ideal gas as μ=kBTln⁡(p/p0)+μ0(T)\mu = k_BT\ln(p/p_0) + \mu_0(T) with an undetermined function μ0(T)\mu_0(T) and a chosen reference pressure, here p0=1.00×105 Pap_0 = 1.00\times10^{5}\,\mathrm{Pa}. The partition function gives F(T,V,N)=−NkBT[ln⁡ ⁣(VNλT3)+1]F(T,V,N) = -Nk_BT\left[\ln\!\left(\frac{V}{N\lambda_T^{3}}\right) + 1\right] λT=h2πmkBT,m=MNA.\lambda_T = \frac{h}{\sqrt{2\pi m k_B T}}, \qquad m = \frac{M}{N_A}. ((a)) From μ=(∂F/∂N)T,V\mu = (\partial F/\partial N)_{T,V} and p=−(∂F/∂V)T,Np = -(\partial F/\partial V)_{T,N}, show that μ=kBTln⁡(p/p0)+μ0(T)\mu = k_BT\ln(p/p_0) + \mu_0(T) with μ0(T)=kBTln⁡ ⁣(p0λT3/kBT)\mu_0(T) = k_BT\ln\!\left(p_0\lambda_T^{3}/k_BT\right), and check that the argument of the logarithm is dimensionless. ((b)) Evaluate μ0\mu_0 at 1000 K1000\,\mathrm{K}, in J and in eV. ((c)) Evaluate μ\mu for the vapour at p=0.0500 bar=5.00×103 Pap = 0.0500\,\mathrm{bar} = 5.00\times10^{3}\,\mathrm{Pa} and 1000 K1000\,\mathrm{K}, in eV. Take h=6.626×10−34 J sh = 6.626\times10^{-34}\,\mathrm{J\,s}, kB=1.381×10−23 J K−1k_B = 1.381\times10^{-23}\,\mathrm{J\,K^{-1}}, NA=6.022×1023 mol−1N_A = 6.022\times10^{23}\,\mathrm{mol^{-1}} and 1 eV=1.602×10−19 J1\,\mathrm{eV} = 1.602\times10^{-19}\,\mathrm{J}.

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