Silver has one conduction electron per atom

PHYSICS · Multi-part · Fermi University Physics · Thermal, Statistical & Complex Systems · Statistical mechanics of ideal classical systems · Quantum statistical mechanics and quantum gases

Thermal Physics, Ch The classical ideal gas from the partition function

Problem

Silver has one conduction electron per atom, giving a conduction-electron number density n=5.86×1028 m−3n = 5.86\times10^{28}\,\mathrm{m^{-3}}. As a first estimate, treat these electrons at T=300 KT = 300\,\mathrm{K} as a classical gas of free particles of mass me=9.109×10−31 kgm_e = 9.109\times10^{-31}\,\mathrm{kg}, ignoring their mutual repulsion and the lattice. Take h=6.626×10−34 J sh = 6.626\times10^{-34}\,\mathrm{J\,s} and kB=1.381×10−23 J K−1k_B = 1.381\times10^{-23}\,\mathrm{J\,K^{-1}}, and use λT=h/2πmkBT\lambda_T = h/\sqrt{2\pi mk_BT}. ((a)) Estimate the thermal de Broglie wavelength of an electron at 300 K300\,\mathrm{K}. ((b)) Evaluate the degeneracy parameter nλT3n\lambda_T^3. ((c)) Feed your result into the Sackur-Tetrode formula S=NkB ⁣[−ln⁡(nλT3)+52]S = Nk_B\!\left[-\ln(n\lambda_T^3) + \tfrac52\right] and give S/NkBS/Nk_B. What does the sign tell you about applying the classical formulae of this chapter to the electrons in a metal?

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